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The air standard cycles for the same maximum pressure and temperature and heat rejection:

  • A.\(\eta_{dual} \gt \eta_{otto} \gt \eta_{diesel}\)
  • B.\(\eta_{otto} \gt \eta_{diesel} \gt \eta_{dual}\)
  • C.\(\eta_{diesel} \gt \eta_{dual} \gt \eta_{otto}\)
  • D.\(\eta_{otto} \gt \eta_{dual} \gt \eta_{diesel}\)

Answer: C

The order is \(\eta_{diesel} \gt \eta_{dual} \gt \eta_{otto}\).

When the maximum pressure and temperature are fixed (the practical limit of the engine) along with the heat rejected, the Otto cycle needs the lowest compression ratio to stay within the pressure limit, and the Diesel cycle can use the highest. On a T-s diagram the Diesel cycle then receives the most heat for the same heat rejected, so it is the most efficient, the Otto cycle the least, and the dual cycle lies between.

This is the reverse of the comparison at the same compression ratio, where the Otto cycle is the most efficient, which is why options ranking Otto first are wrong here.

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