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Discussion

In the following reaction

2-Methyl-1,3-dithiane with n-BuLi and phenyl vinyl sulfoxide gives X; X with (i) xylene, reflux, (ii) HgCl2, CdCO3, H2O gives Y

the major products X and Y, respectively, are:

  • A.2-Methyl-2-vinyl-1,3-dithiane and methyl vinyl ketone
  • B.2-Methyl-2-(2-phenylsulfinylethyl)-1,3-dithiane and 4-phenylbutan-2-one
  • C.2-Methyl-2-(2-phenylsulfinylethyl)-1,3-dithiane and methyl vinyl ketone
  • D.2-Methyl-2-phenylsulfinyl-1,3-dithiane and an acetyl phenyl sulfone

Answer: C

X and Y are 2-methyl-2-(2-phenylsulfinylethyl)-1,3-dithiane and methyl vinyl ketone.

n-BuLi removes the C2 proton of 2-methyl-1,3-dithiane, giving an acyl-anion equivalent. It adds in conjugate fashion to phenyl vinyl sulfoxide, a Michael acceptor, so X carries a CH2CH2S(O)Ph chain on C2.

Refluxing in xylene triggers a syn (Ei) sulfoxide elimination through a five-membered cyclic transition state, losing PhSOH and leaving a vinyl group. HgCl2 with CdCO3 in water then hydrolyses the dithiane to the ketone, giving CH3COCH=CH2, methyl vinyl ketone. The phenyl vinyl sulfoxide has served as a vinyl cation equivalent.

(A) shows the vinyl compound as X, but the elimination needs the heating of the second step. (B) keeps a phenyl in Y, though phenyl leaves with the sulfur. (D) has the anion attacking sulfur rather than the alkene.

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