Discussion
Benzenamine reacts with ethanoic anhydride to give
Answer: C
The product is N-phenylethanamide (acetanilide).
Ethanoic anhydride acetylates the -NH2 group of benzenamine (aniline): one acetyl group replaces a hydrogen on nitrogen and ethanoic acid is released.
C6H5NH2 + (CH3CO)2O → C6H5NHCOCH3 + CH3COOH
Benzamide and N-phenylbenzamide would need a benzoyl group, from benzoyl chloride, not an acetyl group. Acylation takes place on nitrogen, not on the ring, so the ring-substituted products do not form.
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