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A receiver tuned to \( 1200 \ \mathrm{kHz} \) has an intermediate frequency of \( 455 \ \mathrm{kHz} \) with high-side injection. The local oscillator runs at

  • A.745 kHz
  • B.455 kHz
  • C.1200 kHz
  • D.1655 kHz

Answer: D

High-side injection puts the oscillator above the signal:

\[ f_{LO} = 1200 + 455 = 1655 \ \mathrm{kHz} \]

so 1655 kHz. 745 kHz is low-side injection, which is also workable but requires a wider oscillator tuning ratio and is therefore less common in broadcast receivers. 455 kHz is the intermediate frequency itself. And 1200 kHz is the signal. The choice of side affects the image frequency, which is the next thing to check.

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