Discussion
The perimeter of a square is 48cm. The area of rectangle is 4cm2 less than the area of the square. If length of the rectangle is 14cm, then its perimeter is
Answer: B
Work from the square to the rectangle.
\[ \text{side of square} = \frac{48}{4} = 12 \text{ cm} \quad\Longrightarrow\quad A = 144 \text{ cm}^{2} \]
\[ A_{\text{rectangle}} = 144 - 4 = 140 \text{ cm}^{2} \]
\[ \text{breadth} = \frac{140}{14} = 10 \text{ cm} \]
\[ \text{perimeter} = 2(14 + 10) = 48 \text{ cm} \]
The rectangle's perimeter coincidentally matches the square's, even though its area is smaller - equal perimeters do not imply equal areas, and the square is always the larger for a given perimeter.
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