Discussion
The transition energy of the electron from higher to lower level is 3.0 × 10-19 J. The wavelength of the emitted light is about
(h = 6.625 × 10-34 J s, c = 3 × 108 m s-1)
Answer: B
The wavelength is about 660 nm.
Use \(E = \frac{hc}{\lambda}\), so \(\lambda = \frac{hc}{E}\).
\[ \begin{aligned} \lambda &= \frac{6.625 \times 10^{-34} \times 3 \times 10^{8}}{3.0 \times 10^{-19}} \\ &= 6.625 \times 10^{-7}\ \text{m} \approx 660\ \text{nm} \end{aligned} \]
This is red light. 330 nm is half the answer, and 990 nm one and a half times it. Light of this wavelength is in the visible region; 330 nm and 310 nm would be ultraviolet.
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