Discussion
In hydrogen spectrum, the shortest wavelength of Bracket series is produced during the transition between the states
Answer: D
The transition is \(n_{2} = \infty\) and \(n_{1} = 4\).
The Brackett series consists of transitions ending on n = 4. Its wavelengths satisfy \(\frac{1}{\lambda} = R\left(\frac{1}{4^{2}} - \frac{1}{n_{2}^{2}}\right)\). The shortest wavelength means the largest energy gap, which is from \(n_{2} = \infty\), the series limit.
5 to 4 is the longest wavelength of the Brackett series. Transitions ending on n = 1, 2 or 3 belong to the Lyman, Balmer and Paschen series.
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