Discussion
ASCII code has 128 characters, which are binary coded. If a computer generates \(10^{6}\) characters per second, then minimum band width required to transmit this signal will be
Answer: C
With 128 characters, each character needs 7 binary digits, since \(2^7 = 128\). At \(10^6\) characters per second the signalling rate is 7 million bits per second, so the answer is 7 mbps (option C).
\[ R = 7 \times 10^{6}\ \text{bits/s} = 7\ \text{Mbps} \]
The value 14 mbps (B) takes 14 bits per character, and 1.4 mbps (A) and 0.7 mbps (D) assume 1.4 and 0.7 bits per character, none of which fits a 7-bit code.
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