Discussion
An oscilloscope has a bandwidth of 100 MHz. Its rise time is about
Answer: D
Correct answer: 3.5 ns
\[ t_r = \frac{0.35}{BW} = \frac{0.35}{100\times10^{6}} = 3.5\ \mathrm{ns}. \] The constant 0.35 comes from the response of a single-pole system between the ten and ninety per cent points, and the relation is why bandwidth and rise time are two ways of quoting the same limitation. Note also that the instrument and the signal add in quadrature, so a scope must be several times faster than the edge it is to measure honestly.
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