Discussion
A cyclone handles \( 1.8 \) m\(^3\)/s of air through an inlet of \( 0.15 \) m\(^2\). The inlet velocity is
Answer: C
Correct answer: 12.0 m/s
Velocity is volumetric flow divided by area:
\[ v = \frac{1.8}{0.15} = 12.0\ \mathrm{m/s} \]
Inlet velocity governs cyclone performance directly, since the centrifugal force separating the dust from the air rises with its square. Too low and fine material escapes with the exhaust; too high and pressure drop and erosion rise steeply. Design velocities for grain dust cyclones typically fall in the range of 12 to 20 m/s, so this machine sits at the gentle end.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development