Discussion
In a dielectric, the power loss is proportional to :
where \(\omega\) is the angular frequency of applied electric field.
Answer: A
The power loss is proportional to \(\omega\).
For a dielectric in an alternating field, the power dissipated per unit volume is
\[ \begin{aligned} P &= \frac{1}{2}\omega\epsilon_{0}\epsilon''E_{0}^{2} \\ &= \frac{1}{2}\omega\epsilon_{0}\epsilon' \tan\delta\, E_{0}^{2} \end{aligned} \]
where \(\epsilon''\) is the loss factor and \(\tan\delta\) the loss tangent. Each cycle loses a fixed fraction of the stored energy, so for a given loss factor the power lost is proportional to the number of cycles per second, that is to \(\omega\). This is why dielectric heating (as in microwave ovens) works at high frequencies. The other powers of \(\omega\) do not follow from this relation.
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