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Why does a diode's reverse recovery cause loss in a switching supply?

  • A.The junction capacitance discharges into the load
  • B.The stored charge is dissipated in the diode's package
  • C.Current flows briefly while the voltage is reversed
  • D.The forward drop rises during the recovery period

Answer: C

During recovery reverse current flows while reverse voltage is already present, so the product is real dissipation, and it recurs every switching cycle. The forward drop is not involved once conduction has ceased, and the capacitance contribution is small by comparison. Any overlap of current and voltage in a switching device is loss, and it is why recovery time matters more as the switching frequency rises. A single measurement chosen to respond to the one asymmetry beats several that respond to shared behaviour.

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