Discussion
A thin layer follows \( MR = \exp(-kt) \) with \( k = 0.25 \) per hour. The moisture ratio after \( 4 \) hours is
Answer: A
Correct answer: 0.368
Substituting into the thin layer model:
\[ MR = \exp(-kt) = \exp(-0.25 \times 4) = \exp(-1) = 0.368 \]
So after four hours the free moisture has fallen to about 37 per cent of its initial value - \( 1/k \) is the time constant, and one time constant removes about 63 per cent of the free moisture. The distractor \( 0.632 \) is that complement, the fraction removed rather than the fraction remaining.
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