Discussion
An AM transmitter has a carrier of \( 400 \ \mathrm{W} \) at full modulation. The power in one sideband is
Answer: D
At an index of unity each sideband carries a quarter of the carrier power:
\[ P_{sb} = \frac{400}{4} = 100 \ \mathrm{W} \]
so 100 watts, with 600 watts radiated in total. 200 W is the pair together. 400 W is the carrier itself. 50 W would correspond to an index of about 0.71. The figure matters because an SSB transmitter conveying the same intelligence needs only that hundred watts, which is the headline efficiency argument for the scheme. It is the same reasoning that decides whether a service keeps its carrier or discards it.
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