Discussion
Using \( p_{ss} = L_{\delta a}\delta_a/(-L_p) \), an aeroplane whose roll damping doubles in magnitude while the aileron moment is unchanged will have a steady roll rate
Answer: B
The damping sits in the denominator, so doubling it halves the steady roll rate while also halving the time constant, making the response quicker to settle at a lower rate. That is the trade behind roll requirements, which constrain both the constant and the achieved rate so that a designer cannot satisfy one by sacrificing the other. Doubling has the relationship inverted. Nothing here leaves the rate unchanged. The square-root factor belongs to frequency relationships, not to this first-order one.
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