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For that cell the free energy change, with \( F = 96\,500 \) C, is about

  • A.\( -106 \) kJ
  • B.\( +212 \) kJ
  • C.\( -424 \) kJ
  • D.\( -212 \) kJ

Answer: D

Correct answer: \( -212 \) kJ

The free energy change is

\[ \Delta G^\circ = -nFE^\circ = -2 \times 96\,500 \times 1.10 = -212\,300 \ \mathrm{J} \approx -212 \ \mathrm{kJ} \]

with \( n = 2 \) because two electrons pass per zinc atom. The negative sign confirms spontaneity, and the magnitude is the maximum electrical work the cell can deliver - obtainable only if the current is drawn reversibly.

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