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The distance between the centres of two identical solid spheres each of radius 5 cm kept in free space is 40 cm. If each one is holding a charge of 2 μC, then the work done in bringing their centres to a separation of 30 cm is

  • A.\(36 \times 10^{-2}\) J
  • B.\(12 \times 10^{-2}\) J
  • C.\(6 \times 10^{-2}\) J
  • D.\(18 \times 10^{-2}\) J
  • E.\(3 \times 10^{-2}\) J

Answer: E

The work done is \(3 \times 10^{-2}\) J.

Outside them, charged spheres act as point charges at their centres. The work equals the increase in potential energy.

\[ \begin{aligned} W &= kq^{2}\left(\frac{1}{0.3} - \frac{1}{0.4}\right) \\ &= 9 \times 10^{9} \times 4 \times 10^{-12} \times \frac{5}{6} \\ &= 0.036 \times \tfrac{5}{6} = 0.03\ \text{J} \end{aligned} \]

The radius of the spheres does not matter as long as they do not overlap. \(12 \times 10^{-2}\) J is the final energy \(\frac{kq^{2}}{0.3}\), not the change.

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