Discussion
For that same fault the heave is about
Answer: D
Correct answer: 43 m
The heave is the horizontal component of the same slip:
\[ \text{heave} = s\cos\delta = 50 \times \cos 30^\circ = 50 \times 0.866 \approx 43 \text{ m} \]Throw and heave are the two components of the net slip, and \( 25^2 + 43^2 \approx 50^2 \) as they must be. At 30 degrees the horizontal displacement is the larger of the two.
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