Discussion
A joint set spaced at 0.3 m intersecting two others at similar spacing gives blocks of about
Answer: C
Correct answer: 0.027 m\( ^3 \)
Three sets at similar spacing intersecting one another cut the mass into roughly cubical blocks of side equal to the spacing:
\[ V = 0.3^3 = 0.027 \ \mathrm{m}^3 \]which is about 70 kilogrammes of rock - small enough to be handled by bolting and mesh, but large enough to kill if it falls from a tunnel roof. The 0.9 answer multiplies rather than cubes, and 0.3 uses the spacing itself.
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