Discussion
A transmitter's phase modulator gives an index of \( 0.4 \) at \( 400 \ \mathrm{kHz} \). To reach an index of \( 5 \), the multiplication factor needed is
Answer: B
Dividing the required index by the available one:
\[ n = \frac{5}{0.4} = 12.5 \]
so about 12.5, which in practice would be built from a chain of doublers and triplers giving twelve or sixteen. The carrier goes to 5 MHz at the same time, and a mixer then shifts it to the operating frequency without further scaling the deviation. 5 and 20 are the index and a plausible chain factor rather than the ratio, and 2 is a single doubler. A single measurement chosen to respond to the one asymmetry beats several that respond to shared behaviour.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development