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The kinetic energy of a moving projectile is determined by

  • A.\(K.E. = \frac{1}{2} MV\)
  • B.\(K.E. = \frac{1}{2} MV^{2}\)
  • C.\(K.E. = MV^{2}\)
  • D.\(K.E. = \sqrt{\frac{1\,MV^{2}}{2}}\)

Answer: B

The kinetic energy of a moving projectile is one half of the mass times the square of the velocity, \(\frac{1}{2}MV^{2}\).

The formula is

\[ K.E. = \frac{1}{2}\,M\,V^{2} \]

Energy depends on the square of the velocity, so doubling the speed makes the energy four times as great, which is why velocity matters more than mass for the wounding power of a bullet.

The expression with V to the first power is the form of the momentum, with a half, and the expression without the half is twice the energy. The square-root expression has no physical meaning here.

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