Discussion
A narrowband FM voice channel uses \( \pm 5 \ \mathrm{kHz} \) deviation with audio to \( 3 \ \mathrm{kHz} \). Carson's rule gives
Answer: C
Applying the rule:
\[ B = 2(5+3) = 16 \ \mathrm{kHz} \]
so 16 kHz, which fits comfortably in a 25 kHz land mobile channel. 10 kHz is twice the deviation, omitting the audio term that matters most at low index. 6 kHz is twice the audio frequency, the narrowband limit that applies only when the index is much less than one. And 25 kHz is the channel spacing rather than the occupied bandwidth.
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