Discussion
What is the output of this C code?
double i;
int main()
{
printf("%g\n",i);
return 0;
}
Answer: A
Correct answer: 0.000000
A file-scope double is zero-initialised, so it holds 0.0. %g chooses the shorter of the fixed and exponential forms, and for zero the answer is 0 either way.
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