Discussion
An aircraft rotates at \( 10 \) degrees with the tail \( 20 \) m behind the main gear. The tail descends by approximately
Answer: B
Correct answer: 3.5 m
The tail swings on an arc about the main gear contact point, so the descent is the arm times the sine of the rotation angle:
\[ 20 \times \sin 10^\circ = 20 \times 0.1736 = 3.47\ \mathrm{m} \]
The available clearance must exceed this, which is why a stretch that lengthens the rear fuselage so directly threatens the rotation angle - a longer arm gives a larger descent for the same rotation.
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