Discussion
Reducing seat pitch from \( 0.81 \) to \( 0.76 \) m in a \( 24.3 \) m cabin allows how many rows?
Answer: B
Correct answer: 31 rows
Divide the cabin length by the new pitch and take the whole number:
\[ \frac{24.3}{0.76} = 31.97 \rightarrow 31\ \text{rows} \]
At 0.81 m the same cabin gave 30 rows, so the reduction buys one row - six seats at six abreast. The gain is modest because the arithmetic is a ratio: a 6 per cent pitch reduction buys about 3 per cent more rows once the result is rounded down.
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