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Boreholes at 30 m centres over a 90 m by 60 m site would number, on a regular grid,

  • A.6
  • B.9
  • C.20
  • D.12

Answer: D

Correct answer: 12

A regular grid at 30 m centres over 90 m by 60 m has four positions along the longer side and three along the shorter, since the first is at zero: \[ \left(\frac{90}{30}+1\right) \times \left(\frac{60}{30}+1\right) = 4 \times 3 = 12. \] Forgetting to add one to each direction gives six, which is the trap in this arithmetic.

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