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G1 and G2 are two graphs as shown :

Two graphs. G1 has six vertices a to f: a at the top, b and c on the sides, d, e and f along the base, with edges a-b, a-c, a-e, b-d, b-f, c-d, c-f, d-e and e-f. G2 has six vertices in two rows of three with many crossing edges between them.

  • A.Both G1 and G2 are planar graphs.
  • B.Both G1 and G2 are not planar graphs.
  • C.G1 is planar and G2 is not planar graph.
  • D.G1 is not planar and G2 is planar graph.

Answer: D

G1 has six vertices and nine edges, and its vertices split into two sets, a, d, f and b, c, e, with each vertex of one set joined to every vertex of the other. That is the complete bipartite graph K3,3, which is not planar by Kuratowski's theorem, so G1 is not planar. G2, as the key reads it, can be redrawn without crossing edges, so it is planar; the key is followed for G2. So G1 is not planar and G2 is planar, option (D), and the options calling G1 planar are wrong.

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