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The geometric sweep-out volume of a collector drop per unit time is

  • A.its volume divided by its terminal velocity
  • B.the number of droplets present in one cubic metre
  • C.its cross sectional area times its fall speed relative to the droplets
  • D.its total surface area multiplied by the ambient supersaturation available

Answer: C

This geometric rate is then multiplied by the collection efficiency to give the actual kernel. Both factors grow with the collector size, which is the source of the accelerating growth. Area and fall speed both rise with the square of the radius.

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