Discussion
If the product of two numbers is 47,915 and their H.C.F. is 37, then their sum is
Answer: B
The sum is 444.
If the H.C.F. is 37, the numbers are \(37a\) and \(37b\), where a and b have no common factor:
\[ \begin{aligned} 37a \times 37b &= 47915 \\ ab &= \frac{47915}{1369} = 35 \end{aligned} \]
Co-prime pairs with product 35 are (1, 35) and (5, 7). The pair (5, 7) gives the numbers 185 and 259:
\[ 185 + 259 = 444 \]
The pair (1, 35) gives 37 and 1295, whose sum, 1332, is not offered. As a check, \(185 \times 259 = 47915\), and both are multiples of 37 with no larger common factor.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development