Discussion
Two normal populations have variances \(\sigma_1^{2}\) = 10 and \(\sigma_2^{2}\) = 20. Two random samples of sizes 25 and 20, independently selected from these populations have variances of \(S_1^{2}\) = 8 and \(S_2^{2}\) = 15, respectively. What is the \(F_{(24, 19)}\) statistic ?
Answer: A
The F statistic is the ratio of the sample variances each divided by its population variance.
\[ F = \frac{S_1^2 / \sigma_1^2}{S_2^2 / \sigma_2^2} \]
\[ F = \frac{8/10}{15/20} \]
\[ F = \frac{0.8}{0.75} \approx 1.07 \]
The nearest value in the options is 1, option A, which is the keyed answer. The values 2, 2.81 and 3.6 are much larger.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development