Discussion
Using the slope of \(0.10\) per degree from the previous relation, the zero-lift angle of that section is
Answer: B
Working back from \(c_l = 0.6\) at \(4^\circ\), the section needs \(0.6/0.10 = 6\) degrees of effective incidence, so the zero-lift angle lies \(6\) degrees below \(4\), that is at \(-2^\circ\). The negative value confirms the section is cambered.
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