Machine-translated by Google. Questions are authored in English.
Top

Discussion

Star-delta starting reduces the starting torque to

  • A.one ninth of its direct-on-line value
  • B.one half of its direct-on-line value
  • C.the same value as direct-on-line starting
  • D.one third of its direct-on-line value

Answer: D

Torque follows the square of the phase voltage, and the phase voltage falls by \( \sqrt{3} \), so the torque falls by three. A load needing more than a third of full-load torque to break away cannot be started this way.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.