Discussion
Statements
T@Y ,Y#G ,G%W
Conclusions
I.G*T II.T$G III.T@G
Answer: E
Correct answer: None of The above
In this set the code reads: \(@\) is “neither smaller nor equal”, so \(>\); \(\#\) is “not smaller than”, so \(\ge\); \(\%\) is “not greater than”, so \(\le\); \(*\) is “neither smaller nor greater”, so \(=\); and \(\$\) is “neither greater nor equal”, so \(<\). The statements become \( T > Y \), \( Y \ge G \) and \( G \le W \), and the first two join: \[ T > Y \ge G. \]
That settles T against G completely. Because the chain contains a strict link, \( T > G \).
I. \( G * T \) asks whether \( G = T \). Definitely false, since \( T > G \).
II. \( T \$ G \) asks whether \( T < G \). Definitely false for the same reason.
III. \( T @ G \) asks whether \( T > G \). True.
So exactly one conclusion holds, and no option says “only III”. The three “either…or” options are wrong for a reason worth understanding: an either-or answer applies only when neither of a complementary pair can be settled individually, so that one of them must hold without our knowing which. Here III is settled, which rules that pattern out. The answer is therefore none of the above.
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