Discussion
If \(V_{DC}\) = 5V is applied to the input of a differentiator circuit its output will be
Answer: A
The output of a differentiator for a d.c. input of 5 V is zero, option (A). An ideal differentiator gives an output \(v_{o} = -RC\,\dfrac{dv_{i}}{dt}\), proportional to the rate of change of the input. A steady d.c. level has a rate of change of zero, so the output is zero, apart from a brief transient at the instant the voltage is applied. A square pulse, option (B), would come from a ramp input. A ramp, option (C), would come from an integrator with a d.c. input. An output of 5 V, option (D), would need a gain that has no basis here.
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