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A mild steel rod of dia 50 mm and length 200 mm has to be turned to a dia 40 mm in one cut for full length using HSS tool with a feed rate of 0.1 mm/ rev. What is the turning time with speed of 200 rpm?

  • A.4 min
  • B.5 min
  • C.10 min
  • D.20 min

Answer: C

The turning time is 10 min.

The reduction from 50 mm to 40 mm is done in one cut, so the tool travels the length of the rod once. Time is length divided by the feed per minute, which is feed per revolution times rpm:

\[ \begin{aligned} T &= \frac{L}{f N} = \frac{200}{0.1 \times 200} \\ &= \frac{200}{20} = 10\ \text{min} \end{aligned} \]

The diameters only fix the depth of cut (5 mm), which does not enter the time for a single pass. 20 min would be two passes, and 5 min and 4 min do not match the feed and speed given.

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