Discussion
A bin of \( 3.0 \) m diameter is filled to \( 8 \) m with grain of bulk density \( 760 \) kg/m\(^3\). The mass stored is
Answer: C
Correct answer: 43.0 tonnes
Find the volume, then multiply by bulk density:
\[ V = \pi r^2 h = \pi (1.5)^2 (8) = 56.5\ \mathrm{m^3} \]
\[ m = 56.5 \times 760 = 42\,977\ \mathrm{kg} = 43.0\ \mathrm{tonnes} \]
Bulk density is the right figure to use, since it already accounts for the voids between kernels. The commonest error is to use the diameter where the radius belongs, which would quadruple the answer.
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