Discussion
In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid ₹ 156 for a journey of 16 km and another person paid ₹ 204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is
Answer: B
The passenger who travelled 30 km paid Rs 240.
Let the fixed charge be f and the charge per km be r.
\[ f + 16r = 156, \quad f + 24r = 204 \]
\[ 8r = 48 \Rightarrow r = 6, \quad f = 156 - 96 = 60 \]
\[ \text{Fare for 30 km} = 60 + 30 \times 6 = 240 \]
So Rs 240 is the fare. The other options come from a wrong rate or a missing fixed charge.
This is an example of a linear equation in two unknowns, and any pair of journeys gives the fixed charge and the rate per kilometre.
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