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A 32-bit X86 system with Windows operating system will have ................. GB as theoretical maximum size of virtual address space.

  • A.4
  • B.8
  • C.16
  • D.32

Answer: A

The theoretical maximum virtual address space is 4 GB.

A 32-bit address can name \(2^{32}\) distinct bytes:

\[ 2^{32} = 4{,}294{,}967{,}296\ \text{bytes} = 4\ \text{GB} \]

On 32-bit Windows this space is split, by default 2 GB for the process and 2 GB for the system, but the total that 32-bit addresses can reach is 4 GB. 8, 16 and 32 GB would need 33, 34 and 35 address bits, which is the mistake of doubling the answer.

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