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The correct increasing order of number of electrons around the central atom in the following molecules is

  • A.\(\mathrm{SF_{6} \lt SCl_{2} \lt PF_{5}}\)
  • B.\(\mathrm{SCl_{2} \lt PF_{5} \lt SF_{6}}\)
  • C.\(\mathrm{PF_{5} \lt SCl_{2} \lt SF_{6}}\)
  • D.\(\mathrm{SCl_{2} \lt SF_{6} \lt PF_{5}}\)
  • E.\(\mathrm{PF_{5} \lt SF_{6} \lt SCl_{2}}\)

Answer: B

The increasing order is \(\mathrm{SCl_{2} \lt PF_{5} \lt SF_{6}}\).

Count the valence electrons around each central atom. In SCl2, sulphur has two bond pairs and two lone pairs: 8 electrons. In PF5, phosphorus forms five bonds: 10 electrons. In SF6, sulphur forms six bonds: 12 electrons.

So the order is \(8 \lt 10 \lt 12\). PF5 and SF6 are the standard examples of an expanded octet; SCl2 obeys the octet rule, so it must come first, which rules out every other order.

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