Discussion
Match List – I with List – II and select the correct answer by using the codes given below the lists :
| List – I | List – II |
|---|---|
| a. Multiplexer | 1. Sequential memory |
| b. De-multiplexer | 2. Converts decimal number to binary |
| c. Shift-register | 3. Data Selection |
| d. Encoder | 4. Routes out many data input with single data output |
Codes : a b c d
Answer: B
The key matches the multiplexer with the item that routes many data inputs to a single data output, so a matches 4, and the de-multiplexer with data selection, so b matches 3. The shift register is a sequential memory, so c matches 1, and the encoder converts a decimal number into binary, so d matches 2. The code is 4 3 1 2. The first option, 3 4 1 2, interchanges the first two pairs, which would call the multiplexer the data selection element and the de-multiplexer the many-to-one device, and the key does not accept that. The answer is 4 3 1 2, as the key has it.
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