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Find the odd man out. 2, 5, 10, 17, 26, 37, 50, 64

  • A.50
  • B.26
  • C.37
  • D.64

Answer: D

Each term is one more than a perfect square.

\[ n^{2} + 1: \quad 2,\; 5,\; 10,\; 17,\; 26,\; 37,\; 50,\; 65 \]

The eighth term should be \( 8^{2} + 1 = 65 \), not 64.

So 64 is the odd man out - a perfect square itself, which is what makes it convincing.

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