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An intermediate formed during the hydroformylation of olefins using Co2(CO)8 as catalyst is

  • A.HCo(CO)\(_{6}\)
  • B.H\(_{4}\)Co(CO)\(_{3}\)
  • C.H\(_{2}\)Co(CO)\(_{4}\)
  • D.HCo(CO)\(_{4}\)

Answer: D

The intermediate is HCo(CO)4.

In the cobalt oxo process, Co2(CO)8 reacts with H2 to give the hydride HCo(CO)4, an 18-electron species. It loses one CO to form the 16-electron HCo(CO)3, which binds the olefin, inserts it into the Co-H bond, takes up CO, inserts that into the Co-alkyl bond to form an acyl, and finally releases the aldehyde by hydrogenolysis, regenerating HCo(CO)4.

HCo(CO)6 would be a 22-electron complex. H4Co(CO)3 and H2Co(CO)4 are not intermediates of the accepted (Heck-Breslow) cycle, whose catalyst-carrying species is the tetracarbonyl hydride.

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