Discussion
The displacement and acceleration of a particle oscillating simple harmonically are respectively 3.0 m and 48.0 ms-2. The angular frequency of the particle is (in s-1)
Answer: E
The angular frequency is 4 s-1.
In simple harmonic motion the acceleration is \(a = -\omega^{2}x\), so in magnitude:
\[ \begin{aligned} \omega^{2} &= \frac{a}{x} = \frac{48}{3} = 16 \\ \omega &= 4 \text{ s}^{-1} \end{aligned} \]
Forgetting the square root gives 16, which is not an option; 6, 3, 5 and 2 do not satisfy \(\omega^{2} = 16\).
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