Machine-translated by Google. Questions are authored in English.
Top

Discussion

The same aircraft has a design thrust-to-weight ratio of \( 0.31 \). The installed thrust required is

  • A.99.2 kN
  • B.198.4 kN
  • C.2064 kN
  • D.640 kN

Answer: B

Correct answer: 198.4 kN

The installed thrust follows from the vertical coordinate of the design point:

\[ T = W \times \frac{T}{W} = 640 \times 0.31 = 198.4\ \mathrm{kN} \]

The distractor \( 99.2 \) halves this, as if the figure applied to one engine of a twin; the diagram's \( T/W \) is always the total installed thrust, and the per-engine rating comes from dividing by the number of engines afterwards. This total is what determines which engines from the available catalogue can be considered.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.