Discussion
A UJT has \(R_{BB} = 10\) K and \(R_{B2} = 4\) K. Its intrinsic stand-off ratio is
Answer: A
The intrinsic stand-off ratio of a UJT is \(\eta = \dfrac{R_{B1}}{R_{BB}}\), where the interbase resistance is \(R_{BB} = R_{B1} + R_{B2}\). With the given values,
\[R_{B1} = 10 - 4 = 6\ \text{k}\Omega\]
\[\eta = \dfrac{6}{10} = 0.6\]
This is the first option. The value 0.4 is the ratio \(R_{B2}/R_{BB}\), which is taken by mistake, and 2.4 and 3.5 are greater than one, which is impossible for a ratio of part of a resistance to the whole.
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