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Alternative A costs 20 000 with annual costs of 6000 over 10 years; B costs 35 000 with annual costs of 3500. At 10 per cent, A's equivalent annual cost is about

  • A.9255
  • B.8000
  • C.11 200
  • D.6000

Answer: A

Correct answer: 9255

\[ EUAC_A = 20{,}000 \times (A/P, 10\%, 10) + 6{,}000 = 20{,}000 \times 0.16275 + 6{,}000 = 3{,}255 + 6{,}000 = 9{,}255. \] The two components pull in opposite directions between the alternatives: A is cheap to buy and dear to run, and B the reverse.

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