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Static temperature is 220 K at Mach 5. Using \( T_0 = T(1 + 0.2M^2) \), the stagnation temperature is

  • A.1100 K
  • B.880 K
  • C.1320 K
  • D.440 K

Answer: C

Substituting gives \( 220 \times 6 = 1320 \) kelvin. Decelerating the flow fully to subsonic speed would deliver that temperature to the combustor before any fuel is burned, which is exactly the problem a scramjet avoids.

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