Discussion
A vehicle of \( 1200 \ \mathrm{kg} \) experiences \( 18 \ \mathrm{kN} \) of thrust and \( 12 \ \mathrm{kN} \) of drag. Its acceleration is
Answer: B
Correct answer: 5 m/s squared
The net force is thrust minus drag, and Newton’s second law gives
\[ a = \frac{F_{net}}{m} = \frac{18\,000 - 12\,000}{1200} = \frac{6000}{1200} = 5 \text{ m/s}^2 \]Using the thrust alone gives 15 m/s squared, which is the usual error: at high speed the drag is a large fraction of the thrust, and the acceleration available is the small difference between two large numbers.
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