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A displacement transducer with a shaft stroke of 3.0 cm, is applied to as shown in figure. The total resistance of the potentiometer is 5 k Ω. The input voltage is 5 V, when the wiper is at 0.9 cm. The value of the output voltage is given by

Potentiometer connected across the input voltage Vin between points A and B; the wiper arm takes the output voltage Vout, with R1 the part above the wiper and R2 the part below it

  • A.1.5 V
  • B.15 V
  • C.0.15 V
  • D.5 V

Answer: A

The output voltage of the potentiometer is the input voltage multiplied by the fraction of the stroke at which the wiper stands. The wiper is at 0.9 cm out of a 3.0 cm stroke, so

\[V_{out} = V_{in} \times \dfrac{0.9}{3.0} = 5 \times 0.3\]

\[V_{out} = 1.5\ \text{V}\]

The output is thus 1.5 V, the first option. The potentiometer only divides the input, so the output cannot exceed 5 V, which rules out 15 V, and 5 V would need the wiper at the very top. A value of 0.15 V is a factor of ten too small.

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