Discussion
A stage of gain \( -150 \) drives an identical stage. The cascade's gain is about
Answer: C
Each stage's load is halved by the next stage's input impedance if the two are equal, so each gain falls to about seventy-five:
\[ (-75) \times (-75) \approx 5600 \]
and with lighter loading the figure rises towards about eleven thousand, the product of one loaded and one unloaded stage. The naive 22500 assumes no loading at all. Two inversions give a positive result, which is worth noting before the magnitude is considered.
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